When treating 8 acres with a weed killer dosage of 0.5 pounds a.i. in 50 gallons of water per acre, how much weed killer is needed?

To determine the total amount of weed killer needed for treating 8 acres, we first need to calculate the total amount of active ingredient (a.i.) required for the entire area. The dosage specified is 0.5 pounds of a.i. per acre.

Multiplying the dosage by the number of acres treated gives us:

0.5 pounds a.i. per acre × 8 acres = 4 pounds a.i.

Now, we know that the application is made in a total volume of 50 gallons of water per acre. For 8 acres, the total volume of water used is:

50 gallons per acre × 8 acres = 400 gallons of water.

The dosage calculation indicates that 4 pounds of a.i. is required in total for the 8 acres. In terms of the weed killer product being used, the amount of the product needed will depend on its concentration of active ingredient.

Assuming that the weed killer is a commercial product containing a certain percentage of a.i. in a gallon of the product, one would divide the total amount of a.i. needed (4 pounds) by the a.i. concentration per gallon to find out how many gallons of the product are needed. However, the calculation provided in the